• let's crank this up a notch ...

    From dart200@user7160@newsgrouper.org.invalid to comp.theory on Wed Sep 17 19:18:10 2025
    From Newsgroup: comp.theory


    hi all, especially olcott!

    first off, why is usenet so annoying to access? jeez... sorry if
    i mess up any conventions. and no edits if i make a typo! such 20th century technology 😮‍💨

    second, olcott could you please tell me the gist of your ideas?

    i stumbled onto your name about 10 years ago when i first started
    contemplating the halting problem. i wrote it down in a document noting that you've been cranking on this since at least 2004! i promptly forgot about
    it until a few days ago going thru my archives, and i'm pleasantly surprised to see you're still active working on this, albeit here in some obscure part
    of computing history...

    third, has anyone here (especially olcott) actually read turing's original arguments on the matter? the decision paradox described by turing, involving whether some input machine is "satisfactory" or not, is slightly different
    than your basic halting paradox, and comes with an additional constraint
    that any resolution to said paradox must abide by. namely: if the resolution to the paradox allows for expressing the computation of the antidiagonal (β) across the sequence of computable numbers .../then ya done goofed!/

    if you haven't, i /highly/ recommend carefully reading thru the first two pages of §8 from /on computable numbers/. they were the /first/ words turing wrote about computing, after defining the underlying model of computing as theory, where he lays down the foundation for undecidability within computing:

    https://www.astro.puc.cl/~rparra/tools/PAPERS/turing_1936.pdf#page=17

    or you can read my thesis on the matter:

    https://www.academia.edu/143540657
    --
    a burnt out swe investigating into why our tooling doesn't involve basic programmatic considerations like halting analysis.

    please excuse my pseudo-pyscript,

    ~ nick
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Wed Sep 17 15:09:13 2025
    From Newsgroup: comp.theory

    On 9/17/2025 2:18 PM, dart200 wrote:

    hi all, especially olcott!

    first off, why is usenet so annoying to access? jeez... sorry if
    i mess up any conventions. and no edits if i make a typo! such 20th century technology 😮‍💨

    second, olcott could you please tell me the gist of your ideas?

    i stumbled onto your name about 10 years ago when i first started contemplating the halting problem. i wrote it down in a document noting that you've been cranking on this since at least 2004! i promptly forgot about
    it until a few days ago going thru my archives, and i'm pleasantly surprised to see you're still active working on this, albeit here in some obscure part of computing history...

    third, has anyone here (especially olcott) actually read turing's original arguments on the matter? the decision paradox described by turing, involving whether some input machine is "satisfactory" or not, is slightly different than your basic halting paradox, and comes with an additional constraint
    that any resolution to said paradox must abide by. namely: if the resolution to
    the paradox allows for expressing the computation of the antidiagonal (β) across the sequence of computable numbers .../then ya done goofed!/

    if you haven't, i /highly/ recommend carefully reading thru the first two pages
    of §8 from /on computable numbers/. they were the /first/ words turing wrote about computing, after defining the underlying model of computing as theory, where he lays down the foundation for undecidability within computing:

    https://www.astro.puc.cl/~rparra/tools/PAPERS/turing_1936.pdf#page=17

    or you can read my thesis on the matter:

    https://www.academia.edu/143540657


    Here is the essence of my work and its validation by Claude AI https://philpapers.org/archive/OLCHPS.pdf
    Four other LLM models also agree.

    This is the summation of 22 years worth of work since 2004.
    25% of all of the postings on comp.theory since 2004 are mine.

    I bypass the whole diagonal argument and delve directly
    into the semantics of the algorithm specifications.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Wed Sep 17 15:18:19 2025
    From Newsgroup: comp.theory

    On 9/17/2025 2:18 PM, dart200 wrote:

    hi all, especially olcott!

    first off, why is usenet so annoying to access? jeez... sorry if
    i mess up any conventions. and no edits if i make a typo! such 20th century technology 😮‍💨


    Google Groups used to provide easy access until
    a spammer ruined it for all of us.

    second, olcott could you please tell me the gist of your ideas?


    I already sent you the key gist of my ideas.

    i stumbled onto your name about 10 years ago when i first started contemplating the halting problem. i wrote it down in a document noting that you've been cranking on this since at least 2004! i promptly forgot about
    it until a few days ago going thru my archives, and i'm pleasantly surprised to see you're still active working on this, albeit here in some obscure part of computing history...


    Here are my many papers. https://www.researchgate.net/profile/Pl-Olcott/research

    third, has anyone here (especially olcott) actually read turing's original arguments on the matter? the decision paradox described by turing, involving whether some input machine is "satisfactory" or not, is slightly different than your basic halting paradox, and comes with an additional constraint
    that any resolution to said paradox must abide by. namely: if the resolution to
    the paradox allows for expressing the computation of the antidiagonal (β) across the sequence of computable numbers .../then ya done goofed!/

    if you haven't, i /highly/ recommend carefully reading thru the first two pages
    of §8 from /on computable numbers/. they were the /first/ words turing wrote about computing, after defining the underlying model of computing as theory, where he lays down the foundation for undecidability within computing:


    As a software engineer I always boil things
    down to their barest essence.

    https://www.liarparadox.org/Peter_Linz_HP_317-320.pdf
    The above paper seems the best because Linz translated
    the HP proof into explicit state changes.

    That is my most important paper https://www.researchgate.net/publication/369971402_Simulating_Termination_Analyzer_H_is_Not_Fooled_by_Pathological_Input_D

    I have had many key insights since then.

    https://www.astro.puc.cl/~rparra/tools/PAPERS/turing_1936.pdf#page=17

    or you can read my thesis on the matter:

    https://www.academia.edu/143540657


    I skimmed the first couple of pages after I logged
    in to Acadamia. You seem to refer to the diagonal,
    my method bypasses it.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Mr Flibble@flibble@red-dwarf.jmc.corp to comp.theory on Wed Sep 17 21:18:52 2025
    From Newsgroup: comp.theory

    On Wed, 17 Sep 2025 15:09:13 -0500, olcott wrote:

    On 9/17/2025 2:18 PM, dart200 wrote:

    hi all, especially olcott!

    first off, why is usenet so annoying to access? jeez... sorry if i mess
    up any conventions. and no edits if i make a typo! such 20th century
    technology 😮‍💨

    second, olcott could you please tell me the gist of your ideas?

    i stumbled onto your name about 10 years ago when i first started
    contemplating the halting problem. i wrote it down in a document noting
    that you've been cranking on this since at least 2004! i promptly
    forgot about it until a few days ago going thru my archives, and i'm
    pleasantly surprised to see you're still active working on this, albeit
    here in some obscure part of computing history...

    third, has anyone here (especially olcott) actually read turing's
    original arguments on the matter? the decision paradox described by
    turing, involving whether some input machine is "satisfactory" or not,
    is slightly different than your basic halting paradox, and comes with
    an additional constraint that any resolution to said paradox must abide
    by. namely: if the resolution to the paradox allows for expressing the
    computation of the antidiagonal (β) across the sequence of computable
    numbers .../then ya done goofed!/

    if you haven't, i /highly/ recommend carefully reading thru the first
    two pages of §8 from /on computable numbers/. they were the /first/
    words turing wrote about computing, after defining the underlying model
    of computing as theory, where he lays down the foundation for
    undecidability within computing:

    https://www.astro.puc.cl/~rparra/tools/PAPERS/turing_1936.pdf#page=17

    or you can read my thesis on the matter:

    https://www.academia.edu/143540657


    Here is the essence of my work and its validation by Claude AI https://philpapers.org/archive/OLCHPS.pdf Four other LLM models also
    agree.

    The LLM prompts you used were carefully crafted such that the LLM context
    was NOT related to the Halting Problem. People who think they can use
    LLMs to prove anything are ignorant at best, cranks at worst.


    This is the summation of 22 years worth of work since 2004. 25% of all
    of the postings on comp.theory since 2004 are mine.

    I bypass the whole diagonal argument and delve directly into the
    semantics of the algorithm specifications.

    You FAIL to bypass the diagonal argument: DD halts.

    /Flibble
    --
    meet ever shorter deadlines, known as "beat the clock"
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From dart200@user7160@newsgrouper.org.invalid to comp.theory on Wed Sep 17 23:02:45 2025
    From Newsgroup: comp.theory


    olcott <polcott333@gmail.com> posted:
    Here is the essence of my work and its validation by Claude AI https://philpapers.org/archive/OLCHPS.pdf
    Four other LLM models also agree.

    llms can be made to agree 1=2 given enough prompting, unfortunately. we really should
    be evaluating llms not based on what they can prove, but on what they can't be prompted to prove. that would show truly critical reasoning. the bubble popping for
    2020s AI will be quite spectacular.

    also, that result fundamentally contradicts itself. the analyser simulated its own
    behavior as a matter of infinite recursion ... but then uses that to return
    a result???

    and if that is the result then shouldn't HHH(DD) -> 0, so Halt_Status = 0, and the
    if statement triggering the goto HERE loop does not run, causing DD() to halt ...
    meaning HHH(DD) should have been 1. the result is just completely nonsensical.

    oh dear olcott. but look i have a resolution to this paradox and u definitely are the
    right track to a degree, i do hope you'll hear me out fully.

    (is there a guide somewhere for usenet markup conventions? like for fixed-width)

    This is the summation of 22 years worth of work since 2004.
    25% of all of the postings on comp.theory since 2004 are mine.

    unfortunately time spent =/= correctness. while i'm sure there is plenty of value
    in the work you did do, even beyond priming you for this engagement, i'm also sure
    that ur missing something about the original argument for exactly why turing established undecidability in computing in the first place. i'm just hoping your
    time spent indicates a willingness to continue engagement, and that if i do swing
    you over, others will 👀👀👀

    I bypass the whole diagonal argument and delve directly
    into the semantics of the algorithm specifications.

    the diagonal that turing is discussing not "by-passable". he's talking about an /actual diagonal/ computed across the sequence of computable numbers: for every r-th
    machine that can "satisfactorily" compute a number, the diagonal computation will
    find it's r-th digit and this becomes the r-th digit on the diagonal.

    the problem turing is worried about is that if such a diagonal is computable, it
    can be used to "diagonalize" the computable numbers like cantor did with the reals.
    turing presumes that if one can compute a diagonal across the computable numbers,
    then this computation could be used to create an anti-diagonal where each digit is the opposite from the true diagonal ... meaning it would be a computable number that can't exist on the total list of computable numbers. contradiction!

    turing even gives a succinct formal proof for this problem:

    let αn be the n-th computable sequence, and let φn(m) be the m-th figure in αn.
    Let β be the sequence with 1-φn(m) as its n-th. figure. Since β is computable,
    there exists a number K [== β computation] such that 1-φn(n) = φK(n) for all n.
    Putting n = K, we have 1 = 2φK(K), i.e. 1 is even. This is impossible.

    the reason that turing goes on in the next page to show how computing the direct diagonal (β') results in an undecidable paradox is to provide a reason why
    the computation of β can't be computed. he does so with a decision paradox that
    isn't /exactly/ like the halting paradox, but very much quite similar.

    if you resolution for decision paradoxes doesn't also show that β isn't,
    then it's not gunna work. i don't think you've yet had awareness of this problem,
    let alone found a resolution to decision paradoxes that also avoids computing a β.
    --
    a burnt out swe investigating into why our tooling doesn't involve basic programmatic considerations like halting analysis.

    please excuse my pseudo-pyscript,

    ~ nick
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Wed Sep 17 18:16:45 2025
    From Newsgroup: comp.theory

    On 9/17/2025 6:02 PM, dart200 wrote:

    olcott <polcott333@gmail.com> posted:
    Here is the essence of my work and its validation by Claude AI
    https://philpapers.org/archive/OLCHPS.pdf
    Four other LLM models also agree.

    llms can be made to agree 1=2 given enough prompting, unfortunately. we really should
    be evaluating llms not based on what they can prove, but on what they can't be
    prompted to prove. that would show truly critical reasoning. the bubble popping for
    2020s AI will be quite spectacular.

    also, that result fundamentally contradicts itself. the analyser simulated its own
    behavior as a matter of infinite recursion ... but then uses that to return
    a result???

    and if that is the result then shouldn't HHH(DD) -> 0, so Halt_Status = 0, and the
    if statement triggering the goto HERE loop does not run, causing DD() to halt ...
    meaning HHH(DD) should have been 1. the result is just completely nonsensical.

    oh dear olcott. but look i have a resolution to this paradox and u definitely are the
    right track to a degree, i do hope you'll hear me out fully.

    (is there a guide somewhere for usenet markup conventions? like for fixed-width)

    This is the summation of 22 years worth of work since 2004.
    25% of all of the postings on comp.theory since 2004 are mine.

    unfortunately time spent =/= correctness. while i'm sure there is plenty of value
    in the work you did do, even beyond priming you for this engagement, i'm also sure
    that ur missing something about the original argument for exactly why turing established undecidability in computing in the first place. i'm just hoping your
    time spent indicates a willingness to continue engagement, and that if i do swing
    you over, others will 👀👀👀

    I bypass the whole diagonal argument and delve directly
    into the semantics of the algorithm specifications.

    the diagonal that turing is discussing not "by-passable". he's talking about an
    /actual diagonal/ computed across the sequence of computable numbers: for every r-th
    machine that can "satisfactorily" compute a number, the diagonal computation will
    find it's r-th digit and this becomes the r-th digit on the diagonal.

    the problem turing is worried about is that if such a diagonal is computable, it
    can be used to "diagonalize" the computable numbers like cantor did with the reals.
    turing presumes that if one can compute a diagonal across the computable numbers,
    then this computation could be used to create an anti-diagonal where each digit
    is the opposite from the true diagonal ... meaning it would be a computable number that can't exist on the total list of computable numbers. contradiction!

    turing even gives a succinct formal proof for this problem:

    let αn be the n-th computable sequence, and let φn(m) be the m-th figure in αn.
    Let β be the sequence with 1-φn(m) as its n-th. figure. Since β is computable,
    there exists a number K [== β computation] such that 1-φn(n) = φK(n) for all n.
    Putting n = K, we have 1 = 2φK(K), i.e. 1 is even. This is impossible.

    the reason that turing goes on in the next page to show how computing the direct diagonal (β') results in an undecidable paradox is to provide a reason why
    the computation of β can't be computed. he does so with a decision paradox that
    isn't /exactly/ like the halting paradox, but very much quite similar.

    if you resolution for decision paradoxes doesn't also show that β isn't, then it's not gunna work. i don't think you've yet had awareness of this problem,
    let alone found a resolution to decision paradoxes that also avoids computing a β.


    The way that the diagonal *is* bypassed is my newest
    work that is not provided anywhere else besides here:

    Halt deciders only report on the actual behavior that
    their actual input finite string actually specifies.

    There never has been an actual input that does the
    opposite of whatever its halt decider decides. All
    of the conventional proofs incorrectly conflate the
    behavior of an actual Turing Machine (not its description)
    with the behavior that the input specifies.

    typedef int (*ptr)();
    int HHH(ptr P);

    int DD()
    {
    int Halt_Status = HHH(DD);
    if (Halt_Status)
    HERE: goto HERE;
    return Halt_Status;
    }


    DD simulated by HHH specifies:
    HHH simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)...

    until HHH aborts its simulation and rejects its input
    or until out-of-memory error.

    This single page sums up 22 years of work: https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c
    Every rebuttal involves provably false assumptions.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From Mr Flibble@flibble@red-dwarf.jmc.corp to comp.theory on Wed Sep 17 23:19:07 2025
    From Newsgroup: comp.theory

    On Wed, 17 Sep 2025 18:16:45 -0500, olcott wrote:

    On 9/17/2025 6:02 PM, dart200 wrote:

    olcott <polcott333@gmail.com> posted:
    Here is the essence of my work and its validation by Claude AI
    https://philpapers.org/archive/OLCHPS.pdf Four other LLM models also
    agree.

    llms can be made to agree 1=2 given enough prompting, unfortunately. we
    really should be evaluating llms not based on what they can prove, but
    on what they can't be prompted to prove. that would show truly critical
    reasoning. the bubble popping for 2020s AI will be quite spectacular.

    also, that result fundamentally contradicts itself. the analyser
    simulated its own behavior as a matter of infinite recursion ... but
    then uses that to return a result???

    and if that is the result then shouldn't HHH(DD) -> 0, so Halt_Status =
    0, and the if statement triggering the goto HERE loop does not run,
    causing DD() to halt ... meaning HHH(DD) should have been 1. the result
    is just completely nonsensical.

    oh dear olcott. but look i have a resolution to this paradox and u
    definitely are the right track to a degree, i do hope you'll hear me
    out fully.

    (is there a guide somewhere for usenet markup conventions? like for
    fixed-width)

    This is the summation of 22 years worth of work since 2004.
    25% of all of the postings on comp.theory since 2004 are mine.

    unfortunately time spent =/= correctness. while i'm sure there is
    plenty of value in the work you did do, even beyond priming you for
    this engagement, i'm also sure that ur missing something about the
    original argument for exactly why turing established undecidability in
    computing in the first place. i'm just hoping your time spent indicates
    a willingness to continue engagement, and that if i do swing you over,
    others will 👀👀👀

    I bypass the whole diagonal argument and delve directly into the
    semantics of the algorithm specifications.

    the diagonal that turing is discussing not "by-passable". he's talking
    about an /actual diagonal/ computed across the sequence of computable
    numbers: for every r-th machine that can "satisfactorily" compute a
    number, the diagonal computation will find it's r-th digit and this
    becomes the r-th digit on the diagonal.

    the problem turing is worried about is that if such a diagonal is
    computable, it can be used to "diagonalize" the computable numbers like
    cantor did with the reals. turing presumes that if one can compute a
    diagonal across the computable numbers, then this computation could be
    used to create an anti-diagonal where each digit is the opposite from
    the true diagonal ... meaning it would be a computable number that
    can't exist on the total list of computable numbers. contradiction!

    turing even gives a succinct formal proof for this problem:

    let αn be the n-th computable sequence, and let φn(m) be the m-th
    figure in αn.
    Let β be the sequence with 1-φn(m) as its n-th. figure. Since β is
    computable, there exists a number K [== β computation] such that
    1-φn(n) = φK(n) for all n.
    Putting n = K, we have 1 = 2φK(K), i.e. 1 is even. This is impossible.

    the reason that turing goes on in the next page to show how computing
    the direct diagonal (β') results in an undecidable paradox is to
    provide a reason why the computation of β can't be computed. he does so
    with a decision paradox that isn't /exactly/ like the halting paradox,
    but very much quite similar.

    if you resolution for decision paradoxes doesn't also show that β
    isn't,
    then it's not gunna work. i don't think you've yet had awareness of
    this problem, let alone found a resolution to decision paradoxes that
    also avoids computing a β.


    The way that the diagonal *is* bypassed is my newest work that is not provided anywhere else besides here:

    Halt deciders only report on the actual behavior that their actual input finite string actually specifies.

    There never has been an actual input that does the opposite of whatever
    its halt decider decides. All of the conventional proofs incorrectly
    conflate the behavior of an actual Turing Machine (not its description)
    with the behavior that the input specifies.

    typedef int (*ptr)();
    int HHH(ptr P);

    int DD()
    {
    int Halt_Status = HHH(DD);
    if (Halt_Status)
    HERE: goto HERE;
    return Halt_Status;
    }


    DD simulated by HHH specifies:
    HHH simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)...

    until HHH aborts its simulation and rejects its input or until
    out-of-memory error.

    This single page sums up 22 years of work: https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c Every
    rebuttal involves provably false assumptions.

    But HHH rejects its input by reporting non-halting to DD which will then
    halt proving that HHH is incorrect.

    /Flibble
    --
    meet ever shorter deadlines, known as "beat the clock"
    --- Synchronet 3.21a-Linux NewsLink 1.2
  • From olcott@polcott333@gmail.com to comp.theory on Wed Sep 17 18:23:24 2025
    From Newsgroup: comp.theory

    On 9/17/2025 6:19 PM, Mr Flibble wrote:
    On Wed, 17 Sep 2025 18:16:45 -0500, olcott wrote:

    On 9/17/2025 6:02 PM, dart200 wrote:

    olcott <polcott333@gmail.com> posted:
    Here is the essence of my work and its validation by Claude AI
    https://philpapers.org/archive/OLCHPS.pdf Four other LLM models also
    agree.

    llms can be made to agree 1=2 given enough prompting, unfortunately. we
    really should be evaluating llms not based on what they can prove, but
    on what they can't be prompted to prove. that would show truly critical
    reasoning. the bubble popping for 2020s AI will be quite spectacular.

    also, that result fundamentally contradicts itself. the analyser
    simulated its own behavior as a matter of infinite recursion ... but
    then uses that to return a result???

    and if that is the result then shouldn't HHH(DD) -> 0, so Halt_Status =
    0, and the if statement triggering the goto HERE loop does not run,
    causing DD() to halt ... meaning HHH(DD) should have been 1. the result
    is just completely nonsensical.

    oh dear olcott. but look i have a resolution to this paradox and u
    definitely are the right track to a degree, i do hope you'll hear me
    out fully.

    (is there a guide somewhere for usenet markup conventions? like for
    fixed-width)

    This is the summation of 22 years worth of work since 2004.
    25% of all of the postings on comp.theory since 2004 are mine.

    unfortunately time spent =/= correctness. while i'm sure there is
    plenty of value in the work you did do, even beyond priming you for
    this engagement, i'm also sure that ur missing something about the
    original argument for exactly why turing established undecidability in
    computing in the first place. i'm just hoping your time spent indicates
    a willingness to continue engagement, and that if i do swing you over,
    others will 👀👀👀

    I bypass the whole diagonal argument and delve directly into the
    semantics of the algorithm specifications.

    the diagonal that turing is discussing not "by-passable". he's talking
    about an /actual diagonal/ computed across the sequence of computable
    numbers: for every r-th machine that can "satisfactorily" compute a
    number, the diagonal computation will find it's r-th digit and this
    becomes the r-th digit on the diagonal.

    the problem turing is worried about is that if such a diagonal is
    computable, it can be used to "diagonalize" the computable numbers like
    cantor did with the reals. turing presumes that if one can compute a
    diagonal across the computable numbers, then this computation could be
    used to create an anti-diagonal where each digit is the opposite from
    the true diagonal ... meaning it would be a computable number that
    can't exist on the total list of computable numbers. contradiction!

    turing even gives a succinct formal proof for this problem:

    let αn be the n-th computable sequence, and let φn(m) be the m-th
    figure in αn.
    Let β be the sequence with 1-φn(m) as its n-th. figure. Since β is
    computable, there exists a number K [== β computation] such that
    1-φn(n) = φK(n) for all n.
    Putting n = K, we have 1 = 2φK(K), i.e. 1 is even. This is impossible. >>>
    the reason that turing goes on in the next page to show how computing
    the direct diagonal (β') results in an undecidable paradox is to
    provide a reason why the computation of β can't be computed. he does so >>> with a decision paradox that isn't /exactly/ like the halting paradox,
    but very much quite similar.

    if you resolution for decision paradoxes doesn't also show that β
    isn't,
    then it's not gunna work. i don't think you've yet had awareness of
    this problem, let alone found a resolution to decision paradoxes that
    also avoids computing a β.


    The way that the diagonal *is* bypassed is my newest work that is not
    provided anywhere else besides here:

    Halt deciders only report on the actual behavior that their actual input
    finite string actually specifies.

    There never has been an actual input that does the opposite of whatever
    its halt decider decides. All of the conventional proofs incorrectly
    conflate the behavior of an actual Turing Machine (not its description)
    with the behavior that the input specifies.

    typedef int (*ptr)();
    int HHH(ptr P);

    int DD()
    {
    int Halt_Status = HHH(DD);
    if (Halt_Status)
    HERE: goto HERE;
    return Halt_Status;
    }


    DD simulated by HHH specifies:
    HHH simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)
    that simulates DD that calls HHH(DD)...

    until HHH aborts its simulation and rejects its input or until
    out-of-memory error.

    This single page sums up 22 years of work:
    https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c Every
    rebuttal involves provably false assumptions.

    But HHH rejects its input by reporting non-halting to DD which will then
    halt proving that HHH is incorrect.

    /Flibble




    The behavior of main-->DD-->HHH(DD) is not in the scope of HHH.
    You are smart enough to know what an argument to a function is.
    DD() is not an argument to the function HHH. A finite string
    of x86 machine code is the actual argument.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
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  • From dbush@dbush.mobile@gmail.com to comp.theory on Wed Sep 17 19:30:38 2025
    From Newsgroup: comp.theory

    On 9/17/2025 7:23 PM, olcott wrote:
    The behavior of main-->DD-->HHH(DD) is not in the scope of HHH.

    Then HHH is DISQUALIFIED from being a halt decider:


    Given any algorithm (i.e. a fixed immutable sequence of instructions) X described as <X> with input Y:

    A solution to the halting problem is an algorithm H that computes the following mapping:

    (<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
    (<X>,Y) maps to 0 if and only if X(Y) does not halt when executed directly

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  • From Richard Heathfield@rjh@cpax.org.uk to comp.theory on Thu Sep 18 01:13:54 2025
    From Newsgroup: comp.theory

    On 18/09/2025 00:23, olcott wrote:

    <snip>

    The behavior of main-->DD-->HHH(DD) is not in the scope of HHH.

    If you say so.

    You are smart enough to know what an argument to a function is.

    Are you?

    DD() is not an argument to the function HHH.

    DD() is a function call.

    DD, however, is very much an argument to the function HHH,

    A finite string
    of x86 machine code is the actual argument.

    Not according to C rules, it isn't.

    What HHH gets is a function pointer, DD by name.

    DD is an argument to HHH, and to claim otherwise is flat out
    bullshit. You don't like it? Take it up with ISO.
    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within
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  • From olcott@polcott333@gmail.com to comp.theory on Wed Sep 17 19:41:27 2025
    From Newsgroup: comp.theory

    On 9/17/2025 7:13 PM, Richard Heathfield wrote:
    On 18/09/2025 00:23, olcott wrote:

    <snip>

    The behavior of main-->DD-->HHH(DD) is not in the scope of HHH.

    If you say so.

    You are smart enough to know what an argument to a function is.

    Are you?

    DD() is not an argument to the function HHH.

    DD() is a function call.

    DD, however, is very much an argument to the function HHH,

    A finite string
    of x86 machine code is the actual argument.

    Not according to C rules, it isn't.

    What HHH gets is a function pointer, DD by name.

    DD is an argument to HHH, and to claim otherwise is flat out bullshit.
    You don't like it? Take it up with ISO.


    It is as a matter of verified fact an argument
    to the HHH function as proven by the fact that
    this is what the x86 assembly language of HHH
    (translated from C) specifies.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
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  • From Richard Heathfield@rjh@cpax.org.uk to comp.theory on Thu Sep 18 02:08:39 2025
    From Newsgroup: comp.theory

    On 18/09/2025 01:41, olcott wrote:
    On 9/17/2025 7:13 PM, Richard Heathfield wrote:
    On 18/09/2025 00:23, olcott wrote:

    <snip>

    The behavior of main-->DD-->HHH(DD) is not in the scope of HHH.

    If you say so.

    You are smart enough to know what an argument to a function is.

    Are you?

    DD() is not an argument to the function HHH.

    DD() is a function call.

    DD, however, is very much an argument to the function HHH,

    A finite string
    of x86 machine code is the actual argument.

    Not according to C rules, it isn't.

    What HHH gets is a function pointer, DD by name.

    DD is an argument to HHH, and to claim otherwise is flat out
    bullshit. You don't like it? Take it up with ISO.


    It is as a matter of verified fact

    It's a matter of terminology specified by an International Standard.
    --
    Richard Heathfield
    Email: rjh at cpax dot org dot uk
    "Usenet is a strange place" - dmr 29 July 1999
    Sig line 4 vacant - apply within
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