On 2026-04-22 01:48, olcott wrote:
On 4/22/2026 2:19 AM, Mikko wrote:
It is a syntax error to use open variables φ in a definition.Besides
KnownTrue is a bad name for a symbol that does not refer to knowledge.
KnownTrue :=
There exists a sequence of back-chained inference
steps Γ in PA such that φ reaches the axioms of PA
That doesn't solve the problem of the open variable.
You could solve this by changing it to KnownTrue(φ) := ...
But I still think your better off dispensing with the formalism and
simply expressing your ideas in English since you always mangle the formalism.
Why not simply say:
A proposition is known to be true if there is a sequence of back-chained inference steps from that proposition to the axioms of Peano Arithmetic.
I'm not saying I agree with the above, but at least it is more clear
than your attempts at formalism.
On 23/04/2026 00:06, André G. Isaak wrote:
On 2026-04-22 01:48, olcott wrote:
On 4/22/2026 2:19 AM, Mikko wrote:
It is a syntax error to use open variables φ in a definition.Besides
KnownTrue is a bad name for a symbol that does not refer to knowledge. >>>>
KnownTrue :=
There exists a sequence of back-chained inference
steps Γ in PA such that φ reaches the axioms of PA
That doesn't solve the problem of the open variable.
You could solve this by changing it to KnownTrue(φ) := ...
But I still think your better off dispensing with the formalism and
simply expressing your ideas in English since you always mangle the
formalism.
Why not simply say:
A proposition is known to be true if there is a sequence of back-chained
inference steps from that proposition to the axioms of Peano Arithmetic.
I'm not saying I agree with the above, but at least it is more clear
than your attempts at formalism.
"A proposition is known to be true [at least when] ..." isn't the same
as "KnownTrue := ...". The former has extra semantics.
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